Three-Phase Circuit Problem-Solve It and Get a Discount

First person to solve this in the comments section will get one or all of my books for a 30% discount. You must show how you got the answer. Must have paypal or cashapp.

JEROME PEDRO got it correct

A three-phase un-grounded circuit with ABC rotation is connected to a resistive load as shown below.

Ra, Rb and Rc are each 22.5 ohms. Voltage Vc Fails open. A volt meter is placed as shown below to determine the voltage.

What will the voltmeter read?
Answer to nearest tenth.

5 thoughts on “Three-Phase Circuit Problem-Solve It and Get a Discount

  1. The wye connected load will experience single phasing and the phase voltage will become half the line voltage. The line current at line C will be zero and Ra and Rb will be series or 2R.
    Iline=Vline/2(R)=Vphase/R. Therefore, Vphase=Vline/2
    so the voltage will read 50VRMS.

  2. The voltage between Line a and b is 173.21 V (100 * sqrt(3)). It is a three phase system. Ra and Rb act as a voltage divider and so the voltage measured is 86.6 V (100*sqrt(3) * 0.5) )

  3. With loss of phase this becomes a single phase circuit. KVL the loop. V1=(100 <0) Vx= I2R V2= (100<-120) I= ( (100 <0) – (100 <-120))/(2×22.5). IR= V(199.74 <12.57)

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